函数返回值，静态动态数组

 function New1() public pure returns(uint,bool){
        return (98,true);
    }
    function New2() public pure returns (uint x,bool b){
        return(5,false);
    }
    function New3() public pure returns (uint x,bool b){  
        x=64;
        b=true;
    }

//承接函数的多种写法
    function New4() public pure  returns (uint x, bool b){
        ( x, b) = New1();
        //只返回一个数据
        //(uint x,) = New1(); 
        //(, bool b) = New1();   
    }
    function New4() public pure  returns (uint , bool){
        (uint x,bool b) = New1();
        return (x,b);  
    }
    function New4() public pure  returns (uint , bool){
        (,bool b) = New1();
        (uint x,) = New1();
        return (x,b);  
    }

uint[] public nums1 = [1,2,3]; //动态数组，长度可变
uint[3] public nums2 = [4,5,6];//定长数组，长度不可变，且必须初始化所有元素

function New1() public {
        nums1.push(4); //向数组尾部添加数据
        x = nums1[1];  //赋值
        delete nums1[1]; //删除原先数据，并填充为0 
        nums1.pop();  //将数组的最后一位弹出
        k = nums1.length; //得出数组长度

    } 

 nums3 = new uint[](nums1.length);

uint[] memory result = new uint[](nums1.length);

for (uint i = 0; i < nums1.length; i++) {
            nums3[i] = nums1[i];
        }
或
 for (uint i = 0; i < nums1.length; i++) {
            result[i] = nums1[i];
        }